Difference between Int32.Parse,Convert.Int32

Int32.Parse Method:
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Converts the string representation of a number to its 32-bit signed integer equivalent.
-When s is a null reference, it will throw ArgumentNullException.
-If s is other than integer value, it will throw FormatException.
-When s represents a number out of range, it will throw OverflowException.

Convert.ToInt32(string):
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Converts the specified string representation of 32-bit signed integer equivalent. This calls in turn Int32.Parse () method.
-When s is a null reference, it will return 0 rather than throw ArgumentNullException.
-If s is other than integer value, it will throw FormatException.
-When s represents a number out of range, it will throw OverflowException.

Int32.TryParse Method:
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Converts the specified string representation of 32-bit signed integer equivalent to out variable, and returns true if it is parsed successfully, false otherwise.
-When s is a null reference, it will return 0.
-If s is other than an integer value, the out variable will have 0.
-When s represents a number out of range, the out variable will have 0


Int32.parse(string)
Int32.Parse (string s)


string s1 = "1234";
string s2 = "1234.65";
string s3 = null;
string s4 = "123456789123456789123456789123456789123456789";

int result;
bool success;

result = Int32.Parse(s1); //-- 1234
result = Int32.Parse(s2); //-- FormatException
result = Int32.Parse(s3); //-- ArgumentNullException
result = Int32.Parse(s4); //-- OverflowException

Convert.ToInt32(string)


For example:
result = Convert.ToInt32(s1); //-- 1234
result = Convert.ToInt32(s2); //-- FormatException
result = Convert.ToInt32(s3); //-- 0
result = Convert.ToInt32(s4); //-- OverflowException


success = Int32.TryParse(s1, out result); //-- success => true; result => 1234
success = Int32.TryParse(s2, out result); //-- success => false; result => 0
success = Int32.TryParse(s3, out result); //-- success => false; result => 0
success = Int32.TryParse(s4, out result); //-- success => false; result => 0